Please bare in mind that the start-up current or "inrush-current" can be as high as 1.5 Amps initially,
 settling down to a low current of around 800mA,    depending on drive manufacturers specifications.

 The circuit above can be made using phenolic  VeroBoard  (TM)  or on a printed circuit board of the layout as shown below.
 The circuit PCB layout ( below ) can be modified ( if you so wish ) larger caps? however works fine as it is layed out (below).
 It would however,be advisable to spend the time and do it correctly , using a small  "self etched"  circuit board and using a
 adequately large heat sink to dissipate the heat ( as a by-product ) of the voltage reduction through the voltage regulators.
 Below, a 15.0 V AC (center tapped dual 7.5 VAC @ 1.amp) 7.5 + 7.5 = 15.0 x 1.414 = 21.21 V DC. Careful with 240 Volts. 
 Alternatively, a 12.6 VAC (center tapped dual 6.3 VAC @ 1.amp) 6.3 + 6.3 =12.6 x 1.414 = 17.816 V DC or thereabouts.
 below, a 15.0 VAC (center tapped dual 7.5 VAC @ 1.amp) 7.5 + 7.5 = 15.0 x 1.414 = 21.21 V DC. Care with 240 Volts. 
 Try to keep the secondary Output voltages to, say 5.0 Volts AC at 1.5 amps, 5V + 5V = 10V x 1.414 = 14.14 V DC or
 thus resulting in less power wasted (dissipated as heat) into a substancial heat sink. Vin must be 2V above Vout.

For calculating the possible amps available from any of the above transformer calculations,
simply multiply DC amps by 0.62 .    eg:   As in the below bridge rectifier circuit, multiply 
Amps DC = 1.5 A x 0.62 = 0.93 Amps or 930 milli Amps.     For a 2 amp calculation, multiply 
Amps DC = 2.0 A x 0.62 = 1.24 Amps or 1240 milli Amps. Note: always use a 4700uF capacitor.